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Coordinate Geometry: Final Assessment

Section A: Core Review

Question 1mcq
The point (−1,1)(-1,1) lies in which quadrant?
A.Quadrant III
B.Quadrant I
C.Quadrant II
D.Quadrant IV
Question 2mcq
The point (−2,1)(-2,1) lies in which quadrant?
A.Quadrant I
B.Quadrant II
C.Quadrant III
D.Quadrant IV
Question 3mcq
What is the distance between (1,−2)(1,-2) and (4,2)(4,2)?
A.55 units
B.44 units
C.77 units
D.2525 units
Question 4mcq
Find the midpoint of the segment joining (−2,2)(-2,2) and (6,−2)(6,-2).
A.(2,1)(2,1)
B.(3,0)(3,0)
C.(8,−4)(8,-4)
D.(2,0)(2,0)
Question 5mcq
Triangle ABCABC has base AB=7AB=7 units on a horizontal line and perpendicular height 66 units. What is its area?
A.1313 square units
B.4242 square units
C.2121 square units
D.2626 square units
Question 6mcq
The point (−3,3)(-3,3) lies in which quadrant?
A.Quadrant I
B.Quadrant II
C.Quadrant III
D.Quadrant IV
Question 7mcq
What is the distance between (1,−1)(1,-1) and (4,3)(4,3)?
A.55 units
B.44 units
C.77 units
D.2525 units
Question 8mcq
Find the midpoint of the segment joining (−6,2)(-6,2) and (2,−2)(2,-2).
A.(−2,1)(-2,1)
B.(−1,0)(-1,0)
C.(8,−4)(8,-4)
D.(−2,0)(-2,0)

Section B: Application and Reasoning

Question 9mcq
Triangle ABCABC has base AB=7AB=7 units on a horizontal line and perpendicular height 77 units. What is its area?
A.1414 square units
B.4949 square units
C.24.524.5 square units
D.2828 square units
Question 10mcq
The point (−4,5)(-4,5) lies in which quadrant?
A.Quadrant I
B.Quadrant II
C.Quadrant III
D.Quadrant IV
Question 11mcq
Find the midpoint of the segment joining (−6,2)(-6,2) and (2,−2)(2,-2).
A.(−2,0)(-2,0)
B.(−1,0)(-1,0)
C.(8,−4)(8,-4)
D.(−2,1)(-2,1)
Question 12mcq
Points A(0,0)A(0,0), B(3,0)B(3,0) and C(0,4)C(0,4) form what type of triangle?
A.Obtuse scalene only
B.No triangle
C.Equilateral triangle
D.Right-angled triangle
Question 13mcq
Which approach correctly demonstrates the idea: Classify simple figures using coordinate distances?
A.Use only a guess because diagrams are always exact.
B.Ignore the given conditions and choose any formula.
C.Use the correct definition or theorem and justify each step with mathematical reasoning.
D.Change the question so the answer becomes easier.
Question 14mcq
A student must solve a computational thinking on grids problem accurately. Which approach shows good step-by-step mathematical thinking?
A.Apply the relevant formula step by step, showing all working.
B.Memorise the answer from a previous similar question without re-deriving.
C.Skip straight to the answer without checking intermediate steps.
D.Round all values to the nearest ten before starting the calculation.
Question 15mcq
In which quadrant does the point (−3,4)(-3,4) lie?
A.Quadrant II
B.Quadrant I
C.Quadrant IV
D.Quadrant III
Question 16mcq
To plot (2,−3)(2,-3), what should you do from the origin?
A.Move 33 units right and 22 units down.
B.Move 22 units up and 33 units right.
C.Move 22 units left and 33 units up.
D.Move 22 units right and 33 units down.

Section C: Challenge and Mixed Practice

Question 17mcq
A point is 44 units left of the origin and 22 units above it. What are its coordinates?
A.(4,−2)(4,-2)
B.(−2,4)(-2,4)
C.(−4,2)(-4,2)
D.(2,−4)(2,-4)
Question 18mcq
The point (−1,3)(-1,3) lies in which quadrant?
A.Quadrant I
B.Quadrant II
C.Quadrant III
D.Quadrant IV
Question 19mcq
On a grid map, the library is at (2,3)(2,3) and the lab is at (2,7)(2,7). How is the lab positioned relative to the library?
A.44 units above it.
B.55 units below it.
C.22 units left.
D.44 units to the right.
Question 20mcq
What is the horizontal distance between (2,5)(2,5) and (8,5)(8,5)?
A.33 units
B.1010 units
C.1313 units
D.66 units
Question 21mcq
The distance formula is based on which theorem?
A.Angle sum property
B.Factor theorem
C.Pythagoras theorem
D.Midpoint theorem
Question 22mcq
Find the distance between (1,2)(1,2) and (4,6)(4,6).
A.44 units
B.55 units
C.77 units
D.2525 units
Question 23mcq
What is the distance between (1,0)(1,0) and (4,4)(4,4)?
A.55 units
B.44 units
C.77 units
D.2525 units
Question 24mcq
Find the midpoint of the segment joining (−2,2)(-2,2) and (6,−2)(6,-2).
A.(2,1)(2,1)
B.(3,0)(3,0)
C.(8,−4)(8,-4)
D.(2,0)(2,0)