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Trigonometric Identities Practice 1: Core Identities

Section A: Identity Foundations

Question 1mcq
Which statement best describes a trigonometric identity?
A.It is an equation with no variables.
B.It is always solved by substituting 4545^\circ.
C.It is true for all allowed values of the angle.
D.It is true for only one angle.
Question 2mcq
Which is an identity rather than an equation to solve for one value?
A.tanA=1\tan A=1 only for A=45A=45^\circ
B.sin2A+cos2A=1\sin^2 A+\cos^2 A=1
C.sinA=12\sin A=\frac12
D.2x+3=72x+3=7
Question 3mcq
In a right triangle, if sinA=oppositehypotenuse\sin A=\frac{\text{opposite}}{\text{hypotenuse}} and cosA=adjacenthypotenuse\cos A=\frac{\text{adjacent}}{\text{hypotenuse}}, which theorem leads to sin2A+cos2A=1\sin^2A+\cos^2A=1?
A.Pythagoras theorem
B.Basic Proportionality Theorem
C.Midpoint theorem
D.Equal tangents theorem
Question 4mcq
If sinA=35\sin A=\frac{3}{5} for acute AA, what is cosA\cos A?
A.25\frac{2}{5}
B.34\frac{3}{4}
C.54\frac{5}{4}
D.45\frac{4}{5}
Question 5mcq
If cosA=1213\cos A=\frac{12}{13} for acute AA, find sinA\sin A.
A.125\frac{12}{5}
B.512\frac{5}{12}
C.513\frac{5}{13}
D.113\frac{1}{13}

Section B: Simplify and Check

Question 6mcq
To derive 1+tan2A=sec2A1+\tan^2A=\sec^2A from sin2A+cos2A=1\sin^2A+\cos^2A=1, what should we divide by?
A.sec2A\sec^2A
B.cos2A\cos^2A
C.sin2A\sin^2A
D.tan2A\tan^2A
Question 7mcq
To derive 1+cot2A=cosec2A1+\cot^2A=\cosec^2A, divide sin2A+cos2A=1\sin^2A+\cos^2A=1 by:
A.sin2A\sin^2A
B.cos2A\cos^2A
C.tan2A\tan^2A
D.cosec2A\cosec^2A
Question 8mcq
Simplify sec2Atan2A\sec^2A-\tan^2A.
A.00
B.sin2A\sin^2A
C.cos2A\cos^2A
D.11
Question 9mcq
When deriving 1+tan2A=sec2A1+\tan^2A=\sec^2A, why must cosAeq0\cos A eq0?
A.Because tangent is always 00.
B.Because secA\sec A is always 11.
C.Because we divide by cos2A\cos^2A.
D.Because sine is never defined.
Question 10mcq
A student cancels sinA\sin A from sinA+cosA\sin A+\cos A and writes 1+cosA1+\cos A. What is wrong?
A.The result should be tanA\tan A.
B.Terms in a sum cannot be cancelled like common factors.
C.sinA\sin A is never cancellable because it is negative.
D.cosA\cos A must be cancelled first.