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Trigonometric Identities Practice 3: Mixed Simplification

Section A: Mixed Identity Use

Question 1mcq
If sinA=817\sin A=\frac{8}{17} for acute AA, find cotA\cot A.
A.178\frac{17}{8}
B.1517\frac{15}{17}
C.158\frac{15}{8}
D.815\frac{8}{15}
Question 2mcq
Simplify tan2A+1sec2A\tan^2A+1-\sec^2A.
A.sec2A\sec^2A
B.00
C.11
D.tan2A\tan^2A
Question 3mcq
Which transformation proves cosA1sinA=1+sinAcosA\frac{\cos A}{1-\sin A}=\frac{1+\sin A}{\cos A}?
A.Multiply numerator and denominator on the left by 1+sinA1+\sin A.
B.Cancel 11 from 1sinA1-\sin A.
C.Replace cosA\cos A with sinA\sin A.
D.Set A=0A=0^\circ only.
Question 4mcq
Simplify secAtanA\frac{\sec A}{\tan A}.
A.sinA\sin A
B.cosA\cos A
C.cotA\cot A
D.cosecA\cosec A
Question 5mcq
Simplify 1cos2A1+cosA\frac{1-\cos^2A}{1+\cos A}.
A.sinA\sin A
B.cosA\cos A
C.1cosA1-\cos A
D.1+cosA1+\cos A

Section B: Restrictions and Errors

Question 6mcq
In simplifying 1cos2A1+cosA\frac{1-\cos^2A}{1+\cos A}, which restriction is needed for cancellation?
A.cosA=1\cos A=1 only
B.1+cosAeq01+\cos A eq0
C.sinA=0\sin A=0
D.tanA=1\tan A=1
Question 7mcq
A student writes sin2A=sinA\sqrt{\sin^2A}=\sin A for every angle. What is the issue?
A.Generally sin2A=sinA\sqrt{\sin^2A}=|\sin A|.
B.The square root is always negative.
C.sin2A\sin^2A is never positive.
D.The correct value is always cosA\cos A.
Question 8mcq
If sin2A=716\sin^2A=\frac{7}{16}, what is cos2A\cos^2A?
A.716\frac{7}{16}
B.2316\frac{23}{16}
C.34\frac{3}{4}
D.916\frac{9}{16}
Question 9mcq
From 1+tan2A=sec2A1+\tan^2A=\sec^2A, what is tan2A\tan^2A equal to?
A.secA1\sec A-1
B.1+sec2A1+\sec^2A
C.sec2A1\sec^2A-1
D.1sec2A1-\sec^2A
Question 10mcq
From 1+cot2A=cosec2A1+\cot^2A=\cosec^2A, what is cot2A\cot^2A equal to?
A.1+cosec2A1+\cosec^2A
B.cosec2A1\cosec^2A-1
C.1cosec2A1-\cosec^2A
D.cosecA1\cosec A-1